In this post, we will see how to reverse a number in java.
Here is simple program to reverse a number.
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package org.arpit.java2blog; import java.util.Scanner; public class ReverseNumberMain { public static void main(String[] args) { int number, reversedNumber=0, remainder; Scanner scan = new Scanner(System.in); System.out.print("Enter a Number : "); number = scan.nextInt(); while(number != 0) { remainder = number%10; reversedNumber = reversedNumber*10 + remainder; number = number/10; } System.out.print("Reverse of the number : " +reversedNumber); scan.close(); } } |
Output:
Enter a Number : 4567
Reverse of the number : 7654
Reverse of the number : 7654
Let’s just observe values of variables at the end of each iteration.
Iteration 0: number = 4567,remainder = 0, reversedNumber = 0
Iteration 1: number = 456,remainder = 7, reversedNumber = 7
Iteration 2: number = 45,remainder = 6, reversedNumber = 76
Iteration 3: number = 4,remainder = 5, reversedNumber = 765
Iteration 4: number = 0,remainder = 4, reversedNumber = 7654
That’s all about reversing a number in java.
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